思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
18:53, 27 февраля 2026Наука и техника。关于这个话题，搜狗输入法2026提供了深入分析
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Crash regression for state machine conflicts: A test specifically checks that calling byobRequest.respond() after enqueue() doesn't crash the runtime. This sequence creates a conflict in the internal state machine — the enqueue() fulfills the pending read and should invalidate the byobRequest, but implementations must gracefully handle the subsequent respond() rather than corrupting memory in order to cover the very likely possibility that developers are not using the complex API correctly.